类型:转载 责任编辑:asp.net 日期:2007/05/23
热门软件下载:
String business_city=哈尔滨;
byte[] tmpbyte=business_city.getBytes("ISO8859_1");
business_city=new String(tmpbyte);
String sql="select * from business_tab where business_city like "+"%"+business_city+"%"
+"";
ResultSet rs=dBBean.executeQuery(sql);//定义结果集,执行sql语句
错误显示:
C:\Tomcat 4.1\work\Standalone\localhost\_\upjidi_0002d1_0002dmain_jsp.java:74: unclosed character literal
String business_city=?????
这个试什么错误,求教。马上结分
网友回答:
String business_city="哈尔滨";